The Russell Equation (R tea R)

This post is quite nonsensical, read at your own peril.

Bertrand Russell is a fantastically interesting character, a passive-activist against the first world war, mathematician, logician, philosopher and social critic. Alongside being one of the co-founders of Analytical Philosophy, co-authering Principia Mathematica and adding to fields such as logic, mathematics, set theory, epistemology – Bertrand came up with two important arguments. They are Russell’s Teapot (the burden of proof lies with the person making scientifically unfalsifiable claim) and Russell’s Paradox (the set R contains all sets that are not members of themselves, is R in the set?). I enjoyed reading up on these two, and simply because they both start with “Russell’s” I thought I’d merge them:

Let me introduce the teapot operator into Cantor’s naive set theory. What this teapot symbol is representing in the equation is twofold: 1) There is an indisputable relation between R and R, 2) That the burden of proof [for a solution] lies with the scientific community. In this case, set theorists, to come up with new axioms and produce a better less fallible system (which they did). The teapot operator basically means “The relationship of the left and the right transcends this system, get a new one.” For example, another application could be to state that P tea NP:

Although I may be getting ahead of myself thinking that the P vs NP argument transcends todays computational theory, hopefully you see where I’m comming from. All in all it was a bit of fun to portray the ideology of the scientific method by continuously putting the onus upon themselves to come up with solutions or corrections.


2 thoughts on “The Russell Equation (R tea R)

  1. Not worth putting up. Tagging it with all these index terms represents a distraction from those few who actually have something significant to say about Cantor, Frege, Russell’s Paradox, and so forth.

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